Question

3 yrs ago the average age of a and b was 18 yrs with c joining them,the average becimes 22 yrs .how old is c now

Answer 1

HELLO FRIEND.....YOUR ANSWER.

Average of ages of a and b = a+b/2 = 18
= a+b = 36

Now including c = a+b+c/3 = 22
= a+b+c = 66
Putting the value of a+b we get...
36 + c = 66
c = 66-36
c = 30
As we are talking about 3 years ago..
so now the age of C will be...

c=30+3= 33

Answer 2

Age problem
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Let A , Band C's Present age is respectively x ,y and Z

then,

Before 3 years,

A's age = (x-3)

B's age = (y-3)

C's age = (z-3)

Average of A and B's age = 18

{(x-3)+(y-3)}/2 = 18

{x-3+y-3} = 36

{x+y -6} = 36

x + y = 36 + 6

x+ y = 42------(1)

When she joined them,

Average age of A , B and C = 22

{(x-3)+(y-3)+(z-3)}/3= 22

{x+y+z-3-3-3}= 66

x+y+z-9 = 66

x+y+z= 66+ 9

x+y+z= 75-------(2)

Now,by using the first equation in second equation,

(x+y)+z=75

(42) + z = 75

z = 75-42

z = 33

So,

C's age will be 33 years.