Question

30^2 + 103xy -7y^2 factorise this

Answer 1

Correct question :–

▪︎ Factorise : 30 x² + 103 xy - 7 y² = 0

ANSWER :–

▪︎ Factors are (15x - y) and (2x + 7y).

EXPLANATION :–

GIVEN :–

• A function 30x² + 103xy - 7y² = 0

TO FIND :–

• Factors = ?

SOLUTION :–

$\\ \implies { \bold{30 {x }^{2} + 103xy - 7 {y}^{2} = 0}}$

• We should write this as –

$\\ \implies { \bold{30 {x }^{2} + 105xy - 2xy- 7 {y}^{2} = 0}}$

$\\ \implies { \bold{15x(2x + 7y) - y(2x + 7y) = 0 }}$

$\\ \implies { \bold{(15x - y)(2x + 7y) = 0 }}$

Hence , The factor of [30x² + 103xy - 7y²] is (15x - y)(2x + 7y)

Answer 2

$\huge\underline{\mathfrak{Question}}$

$30 {x}^{2} + 103xy - 7 {y}^{2}$

$\huge{\mathfrak{Answer}}$

Now, we will factorize it By The Middle Term Spilit

$30 {x}^{2} + 103xy - 7 = 0$

$⟹30 {x}^{2} + 105xy - 2xy - 7 {y}^{2} = 0$

$⟹15x(2x + 7y) - y(2x + 7y) = 0$

$⟹ \: (2x + 7y)(15x - y)$

Therefore, the answer is :-

$(2x + 7y)(15x - y)$

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