Question

30 and 110 Find HCF of given set of numbers.of given number.

Answer 1

30=1,2,3,5,6,10,15,30,

110=1,2,5,10,11,22,55,110,

H.C.F=10

Answer 2

Solution :

We have ,

30 = 2×3×5

110 = 2×5×11

HCF ( 30, 110 ) = 2 × 5

[ Product of the smallest power of

each common prime factors of the

numbers ]

= 10

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