Question

78, 96 and 108 Find HCF of given set of numbers.of given number.

Answer 1

78=13*2*3
96=2^5*3
108=2^2*3^3
hcf=2*3=6

Answer 2

Solution :

Resolving given Numbers into

product of prime :

78 = 2 × 3 × 13

96 = 2×2×2×2×2×3 = 2^5 × 3

108 = 2×2×3×3×3 = 2² × 3³

Now ,

HCF ( 78,96,108 ) = 2 × 3 = 6

[ Since , Product of the smallest power

of each common prime factors of the

numbers ]

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