Question

30.
Find
k so that
at quadratic eq. (K + 1)x^2-2 (k +1)x+1=0 Has equal roots.​

Answer 1

Answer:

For a quadratic equation to have equal roots, the D [discriminant] needs to be equal to zero.

a = k + 1

b = -2(k + 1)

c = 1

D = $b^{2}$ - 4ac = 0

$[-2(k + 1)]^{2}$ - 4(k + 1)1 = 0

4$(k + 1)^{2}$ - 4(k + 1) = 0                     [Divided entire equation by 4]

$(k + 1)^{2}$  - (k + 1) = 0

$k^{2}$ + 2k + 1 - k - 1 = 0

$k^{2}$ + k = 0                                         [Divided entire equation by k]

k + 1 = 0

k = -1

Hope it helps!