Physics, asked by aaronpitta9, 7 months ago

A car starts from rest at a place A and moves along straigght road till it comes to rest at a place b which is at a distance of 450m from a .The car accelerates and decelerates uniformly and rate of its acceleration is double the rate of its deceleration .It takes a total time of 30s to reach from point B to A.Find the time in seconds fr which the car moves the constant velocity during its motion of the maximum speed attained by the car is 72Km/hr...........

Answers

Answered by anshumansingh0035
0

Answer:

nhi malum yrr

Explanation:

jane do nhi malum toh chodo yrr koin dekhta h

Answered by yash6699
1

A car starts from rest at a place A and moves along straigght road till it comes to rest at a place b which is at a distance of 450m from a . The car accelerates and decelerates uniformly and rate of its acceleration is double the rate of its deceleration . It takes a total time of 30s to reach from point B to A.

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