30.Find the 23rd term of an A.P Whose 11th term is 38 and 16th term is 73 .
(2 Points)
178
122
-122
-178
Answers
Answered by
1
let first term of Ap is a and common difference is d
use formula
tn=a+(n-1) d
now
t11=a+(11-1) d=a+10d=38
same way
t16=a+15d=73
solve this equation then
a=-32 and d=7
now t31=a+30d=-32+210=178
Answered by
1
Answer:
122
Step-by-step explanation:
11th term = a + 10d , 16th term = a + 15 d
38 = a + 10 d ( 1 )
73 = a + 15 d ( 2 )
solve ( 1 ) and. ( 2 ) ,
-35 = - 5 d
d = 7
put d in ( 1 ),
a = 38 - 70
a = -32
23rd term = a + 22d
= -32+ 154 = 122
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