Math, asked by vkrakesh1416tt, 4 months ago

30. Find the sum of first 40 positive integers divisible by 6.

Answers

Answered by mkaur14

3

Step-by-step explanation:

We know that the first 40 positive integers divisible by 6 are 6,12,18,....

This is an AP with a = 6 and d = 6.

S40= 20[2(6) +(40-1)6] =20[12+234] =4920.

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