30 g CaCO3 on heating gave 4.4 g of CO2 and 5.6 g of Cao. Show that
these observations are in agreement with law of conservation of mass.
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Answer:
check the question
Explanation:
CaCO3 ~ CaO + CO2
(1mol) ~ (1mol) + (1mol)
(100g) ~ (56g) + (44g )
30g ~ 5.6g + 4.4g ( given)
CaCO3 : 30/100 : 0.3 mol
CaO : 5.6/56 : 0.1 mol
CO2 : 4.4/44 : 0.1 mol
Note :
take CaCO3 as 10g then it's proved
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