Question

30% goods are sold at 5% loss while rest are sold at 10% profit. If there is a total profit of Rs.55, find the worth of goods sold.​

Answer 1

let the total good be 100.

30×95cp/100 + 70×110cp/100 - 100cp = 55

(2850 + 7700 - 10000)cp = 5500

(10550-10000)cp = 5500

550cp = 5500

cp = 10

total cp = 100cp = 10000

Answer 2

Answer:

The total worth of goods sold is Rs.1000.

Step-by-step explanation:

Let the number of goods be $n$ and the cost price be $x$.

Total cost price of the goods is $nx$.

Given 30% goods are sold at 5% loss.

• 30% goods means $\dfrac{30}{100} \times n$
• 5% loss means $\dfrac{100-5}{100} \times x=\dfrac{95}{100} \times x$
• 30% goods are sold at 5% loss gives

        $\dfrac{30}{100} \times n\times\dfrac{95}{100} \times x=\dfrac{3n}{10} \times \dfrac{95x}{100} =\dfrac{285nx}{1000}$

Given rest are sold at 10% profit.

Remaining goods are 100-30=70%

• 70% goods means $\dfrac{70}{100} \times n$
• 10% profit means $\dfrac{100+10}{100} \times x=\dfrac{110}{100} \times x$
• 70% goods are sold at 10% profit gives

        $\dfrac{70}{100} \times n\times\dfrac{110}{100} \times x=\dfrac{7n}{10} \times\dfrac{110x}{100} =\dfrac{770nx}{1000}$

Selling price of all the goods put together is

$=\dfrac{285nx}{1000}+\dfrac{770nx}{1000}=\dfrac{1055nx}{1000}$

Given total profit of Rs.55

Therefore, profit = SP - CP

$\implies 55=\dfrac{1055nx}{1000}-nx$

$\implies 55\times1000 =1055nx-1000nx$

$\implies 55\times1000 =55nx$

$\implies nx=1000$

Therefore, the total worth of goods sold is Rs.1000.