Question

30 gram of urea present in 90gram if water calculate mole fraction of water and urea​

Answer 1

Explanation:

\begin{gathered}n{urea} = 30 \div 60 \\ = 0.5 \\ n{water} = 90 \div 18 \\ = 5 \\ x{urea} = 0.5 \div 0.5 + 5 \\ = 0.5 \div 5.5 \\ = 0.090 \\ x{water} = 5 \div 0.5 + 5 \\ = 0.90\end{gathered}

nurea=30÷60

=0.5

nwater=90÷18

=5

xurea=0.5÷0.5+5

=0.5÷5.5

=0.090

xwater=5÷0.5+5

=0.90