Question

30.
In Figure-8, ABCD is a parallelogram. A semicircle with centre O and the
diameter AB has been drawn and it passes through D. If
B = 12 cm and OD 1 AB, then find the area of the shaded region.
(Use I = 3-14)
(4374)
Figure-8​

Answer 1

Step-by-step explanation:

then subtract the area of triangle form it 1/2b*h

the find the area of parallelogram which is b*h

Answer 2

The area of shaded region is $43.74\ cm^2$ .

Given :

Length of diameter of semicircle ( AB ) is 12 cm .

Therefore , radius ( OD ) should be 6 cm .

So , required area, A = Area of parallelogram - half the area of semicircle

$A=perpendicular\times base - \dfrac{1}{2}(\dfrac{\pi r^2}{2})\\\\A=12\times 6-\dfrac{1}{4}\times 3.14\times 6^2\\\\A=43.74\ cm^2$

So , the area of shaded region is $43.74\ cm^2$ .

Learn More :

Area

https://brainly.in/question/15898339