Question

30 ml of methanol is present in 200ml of its aqueous solution. Then calculate the concentration of solution in volume by volume percentage

Answer 1

GIVEN

Volume of methanol : 30 ml
Volume of the aq. solution : 200 ml
(which is actually 30 ml methanol + 170 ml water)

CALCULATION

We know, % of solute = (vol. of solute / vol. of solution) x 100

So, % of methanol = (30/200) x 100 = 15%

Thus, 15%. (ANSWER)

Answer 2

Answer:-

15%

Explanation is in the above picture...