30% of man's age exceeds one fifth of his age by 6 years find the age of a man
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Let the man’s age be x.
Thus, 30% of his age = 30/100 *x = 0.3x
This exceeds one fifth of his age by 6 years. This implies
0.3x = 1/5x + 6
=>0.3x = x/5 + 6
=>0.3x - x/5 = 6
=>(1.5x - x)/5 = 6
=>0.5x = 30
=>x = 30/0.5
=>x = 300/5
=>x = 60.
Therefore, the man’s age is 60 years.
Answered by
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Given:
30 % of mans age = 1 / 5 of the mans age + 6 years
To find:
The age of the man.
Solution:
30 % of the mans age = 30 / 100
0.3 of the mans age
Solving,
0.3 of mans age = 1/5 of the mans age + 6 years
Grouping the mans age,
0.3 of mans age - 1/5 of the mans age = 6 years
( 1.5 - 1 ) of the mans age / 5 = 6 Years
0.5 of the mans age = 30
The mans age = 30/0.5
The mans age = 60 years
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