Question

if 1 mole of NaCl is doped with10^-3 moles of SrCl2. what is the number of cationic vacancies per mole of NaCl?

Answer 1

Answer:

• 1 mole of SrCl2 → creates one mole cation vacancy.

Given

• 10^–3 mole of SrCl2 → creates 10^–3 × NA number of vacancy.

= 6.02 × 10^20 mol^–1

Answer 2

Answer:

6.023×10^{18} `

Explanation:

The number of cation vacancies created in the lattice of NaClis equal to the number of divalent Sr^{2+} ion added Concentration of Sr^{2} ions =10^{-3} mole per cent

=10^{-3}+100=10^{-5} mol

1 mole of Sr^{2+} contains 6.023×10^{23} Sr^{2+} ions

10^{-5} mole of Sr^{2+} ions contains 6.023×10^{23}×10^{-5} ions.

Therefore the number of cation vacancies in NaCI crystal is 6.023×10^{18} `

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