Question

30% passengers got down from a train at station X, 70% of the remaining got down at station Y If
there are still 1050 passengers in the train how many passengers were there before station (note no
one boarded the train in station X and Y)

Answer 1

Let total be x

30%of x=3x/10

Remaining =x-3x/100=7x/10

70% of 7x/100=49x/100

Still remaining =1050

Total =(3x/10)+(49x/100)+1050

x=(30x+49x)/100+1050

x=79x/100+(105000/100)

x=(79x+105000)/100

100x=79x+105000

21x=105000

x=5000

Mark me as brainliest

Answer 2

Answer:

Step-by-step explanation:Let total be x

30%of x=3x/10

Remaining =x-3x/100=7x/10

70% of 7x/100=49x/100

Still remaining =1050

Total =(3x/10)+(49x/100)+1050

x=(30x+49x)/100+1050

x=79x/100+(105000/100)

x=(79x+105000)/100

100x=79x+105000

21x=105000

x=5000