Math, asked by EdgyBoi777, 11 months ago

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The sides of a triangular field are in the ratio 5:3:4 and its perimeter is 180m.
Find the (i) Area, (ii) Altitude corresponding to the longest side and (iii) The cost of leveling the field at the rate of Rs. 10 per square metre.

Answers

Answered by aradhna06
2

Step-by-step explanation:

let the sides of the triangle be 5x m , 3x m and 4x m

perimeter = 180 m

atp ,

5x + 3x + 4x = 180

12 x = 180

there fore ,

x = 180 / 12 = 15 m

Answered by Abhishek75700
13

Ratio of sides of triangle is given as 5:3:4

let the sides are 5x, 3x, 4x

according to the question the perimeter is 180m.

Therefore,

5x + 3x +4x = 180

x = 15

the sides are,

5 × 15 = 75

3 × 15 = 45

4 × 15 = 60

{i} Area

By using Herons formula

area =  \sqrt{s(s - a)(s - b)(s -c )}

where,

a, b, c are the sides of the triangle and

s =  \frac{a + b + c}{2}

Area => 1,350 m²

{ii} Altitude corresponding to the longest side

Area of triangle is =

 \frac{1}{2}  \times base \times altitude

base = 75

1350 = 1/2 × 75 × altitude

Altitude = 36 m

{iii} Cost of leveling the ground

per meter square = 10 ₹

1350 meter square = 1350 × 10 = 13500₹

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