Math, asked by kniku464, 2 days ago

30. Subtract 5a ^ 3 - 3a ^ 2 + 9 from the sum of a ^ 3 - 4a ^ 2 + 6a + 2 and 8a ^ 3 + a + 4​

Answers

Answered by meitz343
0

Answer:

x+(2a

2

+3a+2)+(3a

2

−4a+1)=8+13a+7a

2

=x+5a

2

−a+3=8+13a+7a

2

⇒x=7a

2

+13a+8−5a

2

+a−3

x=2a

2

+14a+5.

Answered by juligogoi2008
1

Answer:

=(4a³ - a² +7a - 3)

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Step-by-step explanation:

{(a³ - 4a² + 6a + 2) + (8a³ + a + 4)} - (5a³ - 3a² + 9)

=(a³ - 4a² + 6a + 2 + 8a³ + a + 4) - (5a³ - 3a² + 9)

=(a³ + 8a³ - 4a² + 6a + a + 2 + 4) - (5a³ - 3a² + 9)

=(9a³ - 4a² + 7a + 6) - (5a³ - 3a² + 9)

=(9a³ - 4a² + 7a + 6 - 5a³ + 3a² - 9)

=(9a³ - 5a³ - 4a² + 3a² + 7a + 6 - 9)

=(4a³ - a² +7a - 3)

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