Question

30.
The heat generated in 592 resistor due to current
flowing through it is 10 cal per sec. find the heat
generated in 422 resistor (in cal/sec.).
​

Answer 1

Answer:

i'=i(resistor of opposite branch/total resistance )

let current flowing through 5 ohms be I' and current through 4 ohms be I"

Then,

I"=I'(5/6+4)=I'/2

p1=(I'")5=10 cal/sec

p2=(I"")4=(I'"/4)4=I'"=2 cal/sec

therefore the answer is 2 cal/sec

Explanation:

I'=I 1

I"=I 2