30.
The heat generated in 592 resistor due to current
flowing through it is 10 cal per sec. find the heat
generated in 422 resistor (in cal/sec.).
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Answer:
i'=i(resistor of opposite branch/total resistance )
let current flowing through 5 ohms be I' and current through 4 ohms be I"
Then,
I"=I'(5/6+4)=I'/2
p1=(I'")5=10 cal/sec
p2=(I"")4=(I'"/4)4=I'"=2 cal/sec
therefore the answer is 2 cal/sec
Explanation:
I'=I 1
I"=I 2
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