Question

30. Two pipes running together can fill a tank in 11 minutes. If one pipe takes 5 minutes more than the
other to fill the tanki separately, find the time in which cach pipe would fill the tank separately.​

Answer 1

Question:

Two pipes running together can fill a tank in 11 minutes. If one pipe takes 5 minutes more than the

Two pipes running together can fill a tank in 11 minutes. If one pipe takes 5 minutes more than theother to fill the tanki separately, find the time in which cach pipe would fill the tank separately.

Solution:

T= time

Pipe 1 flow rate/min = 1/T (lit/min)

pipe 2 flow rate (lit/min) = t/(t+5)lit/min

flow rate of both pipes ( together ) lit/min

[1/(T)+1/(T+5)] lit per minute (in 1 minute )

T+5+t/t(t+5) = (2t+5)/t(t+5) lit/min

11(2t+5) = t^2 + 5t

22t + 55 = t^2 + 5t

t^2 - 17 t - 55

t = -b + √ b^2 - 4a / 52a

t = 17 + √(.17)^2-4×1×(-55)/2×1

T= 17 + √289+220/2

T = 17 + 22.56/25

T= 39.56/2

T = 19.78

pipe 1 = 19.78

pipe 2 = 19.78 + 5

= 24.78

:)

Answer 2

Answer:

wait...

Step-by-step explanation:

by checking the solution u may get the answer in a right way