Math, asked by Abhishu, 1 year ago

_ + _ + _ = 30
Use the digits
1, 3, 5, 7, 9, 11, 13, 15
You can also repeat the digits.
(Please explain the answer if you can!)

Answers

Answered by poojan
5
it is an impossible condition with the given odd numbers.
the condition is possible if we take the factorial
3!+9+15 = 30
where 3!= 3×2×1
Answered by Anonymous
33

1 + 3! + 5+ 7 + 11 = thirty

Step-by-step explanation:

3! + 3! + 3! + 3! + 3!      = 30 

3! + 1 + 3 + 9 + 11          = 30

1 + 5 + 7 + 3! + 11               = 30

3! + 3! + 3! + 11 + 1             = 30

3! + 3! + 11 + 5 + 1               = 30

11+ 1 + 1 + 3! + 11              = 30

15 + 3 + 3 + 3 + 3!              = 30

13 + 1 + 1 + 9 + 3!            = 30

133! + 3! + 3! + 3! + 3!      = 30 

3! + 1 + 3 + 9 + 11          = 30

 1 + 5 + 7 + 3! + 11               = 30

3! + 3! + 3! + 11 + 1             = 30

3! + 3! + 11 + 5 + 1               = 30

11+ 1 + 1 + 3! + 11              = 30

15 + 3 + 3 + 3 + 3!              = 30

13 + 1 + 1 + 9 + 3!            = 30

 13 + 1 + 3 + 7 + 3!            = 30

 13 + 5 + 3 + 3 + 3!            = 30

11 + 3 + 7 + 3!            = 30

13 + 5 + 3 + 3 + 3!            = 30

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