Question

30 waves pass through a point in 3 seconds. If the distance between two crest is 2 m .calculate (i) frequency. ( ii ) wavelength ​

Answer 1

$\boxed{\orange{\sf Answer}}$

(i) Frequency = 10 Hz

(ii) wavelength = 2m

$\boxed{\orange{\sf Explanation}}$

Given:

• no. of waves = 30

• time = 3 sec

• Distance between two crests = 2m

To Find:

• (i) Frequency
• (ii) wavelength

Solution:

$\green{Frequency( \nu) }$

• No. of waves passes through a given point per one second is called as Frequency
• Unit if frequency is Hz or S^-1

Acc. to question

$\nu = \dfrac{no. \: of \: waves}{total \: time}$

$\nu = \dfrac{30}{3}$

$\nu = 10 Hz$

$\pink{Wavelength (\lambda)}$

• Distance between two wave peaks (crests) is called as Wavelength
• Unit of wavelength is meter(m)

Acc. to the question

$\lambda = dist. \: between \: crests$

$\lambda = 2m$

#$\texttt{\red{Aravind}\: \blue{Reddy}...!}$

Answer 2

$\large\bold\purple{Heya\:Meta\:!!}$

(i) Frequency = 10 Hz

(ii) wavelength = 2m.....