Math, asked by indar9524, 1 year ago

300 apples are distributed equally among among a ,b,c in such a way that 3 times of the number received by a may be equal to 4 times of b and 9 times of



c.The number of apples by b

Answers

Answered by TooFree
2

Question:

300 apples are distributed among A,B and C in such a way that three times of the number received by 'A' may be equal to four times of 'B' and nine times that of 'C'. The number of apples received by 'B' is ....


Answer:

108


Step-by-step explanation:

Total number of apples = 300

A + B + C = 300 ---------------------- [  1  ]


3 times of the number received by 'A' equal to 4 times of 'B'

3A = 4B

4B = 3A

B = 3/4 A  ---------------------- [  2  ]


3 times of the number received by 'A' equal to 9 times that of 'C'.

3A = 9C

9C = 3A

C = 3/9 A

C = 1/3 A ---------------------- [  3  ]


Sub [  2  ] and [  3  ] into [  1  ] :

A + B + C = 300

A + 3/4 A +  1/3 A = 300

25/12 A = 300

25A = 3600

A = 3600 ÷ 25

A = 144


Sub A = 144 into [ 2 ]:

B = 3/4 A

B = 3/4 (144)

B = 108


Sub A = 144 into [ 3 ]:

C = 1/3 A

C = 1/3 ( 144)

C = 48


Answer: The number of apples received by 'B' is 108


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