Question

300 gram of water at 25 degree celsius is added 200 gram of ice at zero degree celsius the final temperature of the mixture is

Answer 1

Answer:

0°C

Explanation:

The heat required for 100g of ice at 0°C to change into

Water at 0°C=mL=100×80×4.2=33,600J…(Equation | )

The heat released by 300g of water at 25∘C to change its

temperature to 0∘C=mcΔT=300×4.2×25=31,500J….(Equation || )

Since the energy in Equation || is less than of Equation | , the

final temperature of th mixture will be 0°C.

Answer 2

Answer:

Explanation:

0 c