Question

300 J of work ia done in sliding a 2 kg block up an inclined plane of height 10 m. Talking g = 10 m/s², work done against friction is :
a). 1000 J
b). 200 J
c). 100 J
d). Zero

Answer 1

change in gravitational potential energy
= mgh
= 2×10×10
= 200J

let 'wf' = work by friction

and net work =w
w = mgh + wf
300 = 200 + wf

so
wf = 100J

hope it helps you
@di

Answer 2

Answer:

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