Question

300 K temperature at 2.0 ´ 104

Pa pressure volume of 0.09 mole CO2

gas is 112.0 ´ 10–3m3

then calculate volume at 4.0 ´ 104

Pa ?​

Answer 1

Given that gamma = 1.33 and Cv = 25.08 J mol^- 1K^- 1 for CO2 (a) For adiabatic condition T2/T1 = (V1/V2)^gamma- 1 T2 = [ (1/27)^1.33 - 1 ] × 300 = 100K ...