Question

300 ml n2 reacts with 300 ml h2 to form nh3 and volume becomes 550ml. Calculate the volume of nh3 produced

Answer 1

Final Answer : 50mL

Steps:
1) We have,
$N_2 + 3H_2 \rightarrow 2 NH_3 \\ \\ At \:t = 0 \:300mL. \quad 300mL \quad 0 \\ \\ At\: t = t : 300-x \quad 300-3x \quad 2x$

Since, Volume and Temperature of gases is assumed to be constant.
we applied no. of moles directly proportional to volume of gas exerted.

Now,
$V_T = 550mL \\ V_{N_2} + V_{H_2} + V_{NH_3} = 550 mL \\ => (300-x ) + (300-3x) + 2x = 550 \\ => x = 25 mL$

Therefore,
Volume of $NH_3$ produced is
2x = 2*25 = 50mL.

Answer 2

Volume of NH3 produced is

2x = 2*25 = 50mL.