3000 is lent out at9% rate of interest. Find the interest which will be received at the end of 2half years
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Answer:
p=3000
r=9%p.a.
t=1yrs
a=?
CI=p(1+R/100)^t-p
CI=3000(100/100+9/100)^1-3000
=3000*109/100-3000
=30*109-3000
=3270-3000
=270
Step-by-step explanation:
Si=p*t*r/100
=3000*1*9/100
=27000/100
=270
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