(30x)+(60y)=4360
here, (y=3x)
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Given that,
30x + 60y = 4360
⇒ 3x + 6y = 436 ...(i)
and y = 3x ...(ii)
Putting y = 3x in (i), we get
3x + 6 (3x) = 436
⇒ 3x + 18x = 436
⇒ 21x = 436
⇒ x = 436/21
Putting x = 436/21 in (ii), we get
y = 3 (436/21)
⇒ y = 436/7
∴ the required solution be
x = 436/21 & y = 436/7
#MarkAsBrainliest
Given that,
30x + 60y = 4360
⇒ 3x + 6y = 436 ...(i)
and y = 3x ...(ii)
Putting y = 3x in (i), we get
3x + 6 (3x) = 436
⇒ 3x + 18x = 436
⇒ 21x = 436
⇒ x = 436/21
Putting x = 436/21 in (ii), we get
y = 3 (436/21)
⇒ y = 436/7
∴ the required solution be
x = 436/21 & y = 436/7
#MarkAsBrainliest
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