Question

the consecutive multiples of 11 is 363.find the three multiples

Answer 1

11(X)+11(X+1) + 11(X+2)= 11x+11x+11+11x+22=33x+33=363
33x=363-33
33x=330
X=10
numbers=X=10
X+1=11
X+2=12

Answer 2

Answer: 110 , 121 and 132

Step-by-step explanation:

Let the number's be x , x+11 , x+22.

x + x + 11 + x + 22 = 363

3x + 33 = 363

3x = 363 - 33 = 330

x = 330/3 = 110

x + 11 = 110 + 11 = 121

x + 22 = 110 + 22 = 132

Hence, the number's are 110 ,121 and 132.