30xy-12x+10y-4 answer answer answer
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Answered by
94
Given Equation is 30xy - 12x + 10y - 4 can be written as
2(15xy - 6x + 5y - 2) --------- (1)
Factors of 15xy - 6x + 5y - 2 = (15xy + 5y) + (-6x - 2)
= 5y(3x + 1) -2(3x + 1)
= (3x + 1)(5y - 2) ----- (2)
Substitute (2) in (1), we get
30xy - 12xy + 10y - 4 = 2(3x + 1)(5y - 2).
Hope this helps!
2(15xy - 6x + 5y - 2) --------- (1)
Factors of 15xy - 6x + 5y - 2 = (15xy + 5y) + (-6x - 2)
= 5y(3x + 1) -2(3x + 1)
= (3x + 1)(5y - 2) ----- (2)
Substitute (2) in (1), we get
30xy - 12xy + 10y - 4 = 2(3x + 1)(5y - 2).
Hope this helps!
Answered by
52
EQUATION GIVEN:-
=30xy-12x+10y-4 ----------------(1)
It could be written as:-
=2 (15xy-6x+5y-2) --------------(2)
Further taking only,
=15xy-6x+5y-2 -----------------(3)
Factorising this we get,
=5y (3x+1) -2 (3x+1) --------------(4)
Here we take 3x+1 common and the remaining we join and form one expression...and so we get=
(5y-2) (3x+1)
But this must be equal to 2 (5y-2) (3x+1)
as in second case 2 was taken out....so we now multiply 2 here...
Hope this helps!
=30xy-12x+10y-4 ----------------(1)
It could be written as:-
=2 (15xy-6x+5y-2) --------------(2)
Further taking only,
=15xy-6x+5y-2 -----------------(3)
Factorising this we get,
=5y (3x+1) -2 (3x+1) --------------(4)
Here we take 3x+1 common and the remaining we join and form one expression...and so we get=
(5y-2) (3x+1)
But this must be equal to 2 (5y-2) (3x+1)
as in second case 2 was taken out....so we now multiply 2 here...
Hope this helps!
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