Question

31 A 2L vessel contains 4 g of Helium and 4 g of He
gas at 27°C. After sometime, 50% of the gas having
higher average speed is removed. What is the
percentage reduction in total pressure if temperature
remains constant?
(1) 66.67%
( 33.33%
(3) 50%
(4) 25%​

Answer 1

Answer:

Volume of vessel=2L

He=4g

$n_{He} =\frac{4}{4} =1mol$

H2=4g

$n_{H} =\frac{4}{2} =2mol$

Total moles=2+1=3mol

T=27C=300K

P=$\frac{nRT}{V}$

P=$\frac{3*0.0820*300}{2L}$

P=36.90atm

50% of the gas having higher average speed is removed.

P=$\frac{(1*1)*0.082*300}{2}$

P=24.6atm

Reduction in pressure=36.9-24.6

                                    =12.3

Then the reduction % will be $\frac{12.3}{36.9} *100$

=33.3%

option 2 is correct

Answer 2

""CORRECT EXPLANATION """"