Question

A batsman deflects a ball by an angle of 90° without changing the initial speed wich is equal to 54km/hr. What is the impulse imparted to ball?(mass of ball=0.15kg)

Answer 1

Answer:

See the above attachment for the solution.

Answer 2

Answer:

Given,

Mass of the ball m=0.15kg.

The initial speed of the ball u=

$54km/h= \frac{54×1000}{60×60} =15m/s$

The final speed of the ball vf=ucos45⁰

The momentum change takes place in the ball in the vertical direction only because the initial and final momentum in the horizontal direction is canceled out.

vi =−ucos45⁰

According to the impulse-momentum theorem,

Impulse=Changeinmomentum

$⇒I=m(v_i - v_f)$

$I=mucos45^0−(−mucos45^0)$

$I=2mucos45^0$

Substitute the value of mass and velocity.

I=2×0.15×15×0.7071

I=3.19kgm/s