Question

31. A lump of clay of mass 10 g travelling withvelocity 10 cm/sec towards east collides hanon with another lump of clay of mass 10travelling with a velocity of 20 cm/sec towardswest. If the two lumps coalesce after collision- what is its velocity if no external force acts onthe system?(1) 5 cm/sec towards east(2) 5 cm/sec towards west​

Answer 1

Explanation:

Given A lump of clay of mass 10 g travelling with velocity 10 cm/sec towards east collides head with another lump of clay of mass 10 travelling with a velocity of 20 cm/sec towards west. If the two lumps coalesce after collision- what is its velocity if no external force acts on the system?

According to law of conservation of linear momentum we get

 So m1v1 + m2v2 = (m1 + m2)V

Where V is the velocity of coalesce particles

10 x 10 – 10 x 20 = - 20 V (since they are in opposite direction)

-100 = - 20 V

So V = 100 / 20

So V = 5 cm / s in east