Question

31. A wire of length 10cm carrying a current
2A is help perpendicular to a uniform
magnetic field of induction 2x10³wb/
m” the force on the wire is
1) 4 × 10-N m 2 40 x 10²N
3) 4 x 10-2N 4) 4 x 100​

Answer 1

Explanation:

DATA

F = ?

B = 2×10^3 T

I = 2 A

L = 10 cm = 0.1 m

@ = 90

F = B I L Sin@

F = ( 2×10^3 )×(2)×(0.1)×sin 90

F = 400 N