Question

31. AB એ P કેન્દ્રિત વર્તુળનો સ્પર્શક છે. જ્યાં, B એ સ્પર્શબિંદુ છે. PA વર્તુળને Cમાં છેદે છે. જો AB = 15 સેમી
અને AC = 9 સેમી હોય, તો વર્તુળની ત્રિજ્યા શોધો.

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Answer 1

Given :- AB is a tangent to a circle with centre P and B is the point of contact. PA intersects the circle at C if AB = 15cm, AC = 9cm .

To Find :-

• Radius of the circle ?

Solution :-

Let us assume that, radius of the circle is r cm.

we know that,

• A tangent to a circle is perpendicular to the radius through the point of contact .

so,

→ ∠ PBA = 90°

now, in right angled ∆PBA , we have,

→ PB² + AB² = PA²

→ r² + 15² = (9 + r)²

→ r² + 225 = 81 + r² + 18r

→ 18r = 225 - 81

→ 18r = 144

→ r = 8 cm. (Ans.)

Hence, Radius of the circle is 8 cm.

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Answer 2

Answer:

Step-by-step explanation: