Question

31. Calculate the molar mass of the following question a. Glucose (C6 H5 oH) b.ethanol ( C2 H5 OH) C. K2Cr2O7

Answer 1

a) c=12

h=1 and o= 16

12*6+1*5+16*1

72+5+16

93 answer

Answer 2

Explanation:

1. C6H5OH

atomic mass of C = 12

atomic mass of H= 1

atomic mass of O= 16

then

molar mass = (6×12)+(5×1)+16+1

= 72+5+17

= 94 g

same as C2H5OH

= (2×12)+(5×1)+16+1

=24+5+17

=46 g

and

atomic mass of k =39.09

atomic mass of cr=51.99

atomic mass of O= 16

then molar mass

=(2×39.09)+(2×51.99)+(7×16)

=78.18+103.98+112

=294.16 g

I hope it's help you. thanks