Question

31. Given that ABC= 0 out of three vectors two are equal in magnitude and
The magnitude of Third vector is 3 times that of either of the two having equal
Magnitude. Then the angles between Vectors are given by
(a) 30°, 60°, 90° (b) X 45°, 45°, 90
(c) 45°, 60°, 90° (d)
900, 135°, 135
2
SIM​

Answer 1

Answer:

Given that A + B + C = 0 . Out of three vectors, two are equal in magnitude and the magnitude of third vector is √(2) times that of either of the two having equal magnitude. Then, the angles between the vectors are given by. ... Angle between B and C, β=135o. Angle between A and C, γ=135o. solution.

Explanation:

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