Math, asked by anneheneaghan, 7 months ago

Sid has £5 to buy apples and bananas. He uses his money like this: He buys 12 apples. Then he buys as many bananas as possible. With his change he buys more apples. With his change he buys more apples. How many apples and bananas does he buy The apples cost 7p each The bananas cost 40p each

Answers

Answered by nmchopra
6

Answer:

Total apples brought=14

Total bananas brought=10

Step-by-step explanation:

Money with Sid =  £5 = 500p

cost of 1 apple= 7

cost of 12 apples =7x12=84

Change left after he buys apples=500-84=416

cost of 1 banana=40

He can buy maximum 10 bananas

cost of 10 bananas=40×10=400

Change left after he buys bananas=416-400=16

Now he can buy 2 more apples

cost of 2 apples =7x2=14

Change left=16-14=2p

Total apples brought=12+2=14

Total bananas brought=10

Answered by GotMathst0do
0

Answer:

Sid bought 23 apples and 9 bananas

Step-by-step explanation:

18x6=£1.08 for apples

£5-1.08= £3.92

392÷40= 9.8 bananas

0.8x40=32p or £0.32

0.32 ÷0.6= 5.33333

5+18 =23

Sid buys 18 apples and 9 bananas with a leftover of £0.32. So, Sid can buy an extra 5 apples. Thus, Sid bought 23 apples and 9 bananas

Similar questions