31. How much molecular mass of NaCl is obtained experimentally using colligative properties ?
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How much molecular mass of NaCl is obtained experimentally using colligative properties?
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As concentration of particles in the solution is doubled, value of colliegative property is double than expected value and hence molecular mass is halved, i.e., observed molecular mass = 58.5/2 = 29.25
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NaCl has a molar mass of 58.5 g per mole. We can multiply the mass of NaCl in our solution by one over molar mass to to get the number of moles. So, 20 g of NaCl * 1 mole NaCl / 58.5 g NaCl = 0.342 moles NaCl.
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