Question

31. Prove that "the tangent at any point of a circle is perpendicular to the radius
through the point of contact"​

Answer 1

Answer:

⇒ OA < OB (since OA = OC). The same will be the case for all other points on the tangent (l). So OA is shorter than any other line segment joining O to any point on l. Hence, the tangent at any point of a circle is perpendicular to the radius through the point of contact.