31. The tension T in the string shown in figure is
10 kg
u=0.7
30°
777777777777777
(1) Zero
(3) 35/3N
(2) 50 N
(4) (3 – 1) 50 N.
Answers
answer : option (1) zero.
from diagram,
weight of block along plane , W = mgsin30°
= 10kg × 10 m/s² × 1/2
= 50N
weight of block perpendicular to plane = normal reaction between block and wedge = mgcos30°
= 10kg × 10m/s² × √3/2
= 50√3 N
as block has tendency to move downward so, frictional force acting just opposite direction of it.
friction force, fr = μN =0.7 × 50√3 N
= 35√3 N = 60.62 N( approx)
here you can see , frictional force > weight of body along plane
so, body can't move downward, it will be rest and doesn't experience any force.so, tension in string must be zero.
also read similar questions : A block of mass 10 kg is suspended by three strings as shown in figure . the tension t2 is https://brainly.in/question/9438576
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