31g of unknown molecular material is dissolved in 500g of water the resulting solution freezes at 271.14K calculate the molar mass of a material (Kf for water=1.86Kg mom, To of water =273K)
Answers
Answered by
67
Hii dear,
● Answer -
M2 = 62 g/mol
● Explanation -
# Given -
W2 = 31 g
W1 = 500 g
Tf = 271.14 K
Kf = 1.86 Kkg/mol
To = 273 K
# Solution -
Freezing point depression is calculated with formula -
∆Tf = 1000 × Kf.W2 / M2.W1
To - Tf = 1000× Kf.W2 / M2.W1
273 - 271.14 = 1000 × 1.86 × 31 / (M2×500)
M2 = 1000 × 1.86 × 31 / (500×1.86)
M2 = 62 g/mol.
Therefore, molecular mass of solute is 62 g/mol.
Hope this helped.
● Answer -
M2 = 62 g/mol
● Explanation -
# Given -
W2 = 31 g
W1 = 500 g
Tf = 271.14 K
Kf = 1.86 Kkg/mol
To = 273 K
# Solution -
Freezing point depression is calculated with formula -
∆Tf = 1000 × Kf.W2 / M2.W1
To - Tf = 1000× Kf.W2 / M2.W1
273 - 271.14 = 1000 × 1.86 × 31 / (M2×500)
M2 = 1000 × 1.86 × 31 / (500×1.86)
M2 = 62 g/mol.
Therefore, molecular mass of solute is 62 g/mol.
Hope this helped.
Answered by
2
Explanation:
The molar mass of a material is 60g/mol
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