Question

31M5 is a multiple of 9 and two values are obtained by M. why? where M is a digit

Answer 1

Hi ,

According to the divisibility rule ,

Sum of the digits is multiple of 9 then

the number is divisible by 9.

Here ,

31M5

Sum of the digits = 3 + 1 + M + 5

= 9 + M

If M = 0 or 9

Then the sum becomes 9 or 18. Both

numbers are multiples of 9

These values satisfies the divisibility

rule.

Therefore ,

3105 ot 3195 are multiples of 9

I hope this helps you.

:)