Question

32/(24-x)  - 32/ (24+x)  = 1

Solve this as fast as you can....☺

Answer 1

Take LCM (24+X)(24-x)

so

$\frac{32(24 + x) - 32(24 - x)}{(24 - x)(24 + x)} = 1\\ = \frac{768 + 32x - 768 + 32x}{ {24}^{2} - {x}^{2} } = 1 \\ \\ = \frac{64x}{576 - {x}^{2} } = 1 \\ \\ 576 - {x}^{2} = 64x \\ \\ {x}^{2} + 64x - 576 = 0 \\ \\ {x}^{2} + 72x - 8x - 576 = 0 \\ \\ x(x + 72) - 8(x + 72) = 0 \\ \\ (x - 8)(x + 72) \\ \\ x = 8 \\ x = - 72 \\ \\ hp \: its \: helps$

Answer 2

hey.... User here's ur answer

To find value of x = ?

The given equation is 32 / ( 24 - x) - 32 / ( 24 + x ) = 1

Using identity,

( a - b )² = a² - 2ab + b ²

32 - 32 / ( 24 - x )² = 1

0 / ( 576 - 48 x + x ) = 1

we get equation ,

576 - 48x + x

i. e = x - 48x +576 = 0 ( now you can easily find value of x)

x = -72
x = 8

hope it might be helpful !!