Question

32. A block sliding along a horizontal frictionless
surface with a velocity of 2 m si comes to the
bottom of a frictionless inclined plane making
an angle of 30° with the horizontal and comes
to a stop after ascending the inclined plane as
indicated. If g = 10 m s2, the value of his
stops here
0
1) 5 m
2m/s
130°
2) 10 m 3) 0.2 m
4) 2 m​

Answer 1

Answer: it can be solved by using law of conservation of energy

Explanation:

I have even used the angle given to find out the length of the inclined plane to which the block traveled.i have attached the solution