Question

32 a cube + 108 b cube( factorise)

Answer 1

4[(8a) ³+(3b) ³]

4[(2a) ³ +(3b) ³]

4(2a +3b)[ (2a) ² + (2a) (3b) +(3b) ²]

4(2a +3b)(4a²+6a+9b²)

hope it helps you guys

Answer 2

Answer:

4(2a+3b)(4a^2-6ab+9b^2)