32. A force of 20kgf is applied to the smaller piston of a hydraulic machine find
the force exerted on the large piston if diameters of piston being 10cm and
20cm respectively *
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We know that the pressure on both the piston should be same.
Pressureonsmallerpiston=Pressure on larger piston
That is,
Force on smaller/Area of smaller = Force on larger/Area of larger
Therefore,
Forceonlarger= Area of smaller/Force on smaller × Area of larger
⟹ 50/2.5 × 2.5 × 3.14 × 12.5 × 12.5 × 3.14 = 1250kgf
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