Question

32. A solution is obtained by mixing 300 g of 25% solution and
400 g of 40% solution by mass. Calculate the mass percentage of
the resulting solution.​

Answer 1

Explanation:

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Answer

According to question,

300g of 25% solution contains solute = (300 x 25) / 100 = 75g

&

400g of 40% solution contains solute = (400 x 40) / 100 = 160g

Total solute = 75 + 160 = 235g

As given in the question, total solution =300 + 400 = 700g

Percentage of solute in the final solution = (235 x100) / 700 = 33.5%

Percentage of water in the final solution = 100 - 33.5 = 65.5%

Answer 2

➨Given that:

• Mass of Solute in solution A, Ma = [25 × 300]/100 = 75g
• Mass of Solute in solution B, Mb = [40 × 400]/100. = 160g

➨To find:

• Mass Percentage of Solute

⟶Formula:

Mass Percentage of Solute

$= \frac{mass \: of \: solute}{mass \: of \: solution} \times 100$

➨SolutiOn:

⇒ Total mass of Solute in mixture, M = Ma + Mb

= [75 + 160]

= 235g

⇒ Total mass of solution = 300 + 400= 700g

⇒ Mass Percentage of Solute

= 235/700×100

= 33.5%

⇒ Percentage of Water in final solution = 100-33.5

= 66.5%

• ⟶Therefore mass percentage of solute is 33.5% and that of water is 66.5%.

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