Question

32
Find the value of log root2 32​

Answer 1

Answer:

the root of 232 is 2,2,53.

Step-by-step explanation:

53 is a co-prime number that is this number is only divisible by its own number..

Answer 2

Answer:

Concept :

The logarithm is the opposite of exponentiation in terms of function. This indicates that the base b of another fixed number, the logarithm of a given number x, is the exponent that must be raised in order to obtain the given number x. For example, since 1000 = 10 10 10 = 103, the "logarithm base 10" of 1000 is 3, or log10 (1000) = 3. In the simplest instance, the logarithm counts the number of times the same component appears in repeated multiplication. In cases where there is little chance of confusion or when the base is irrelevant, such as in big O notation, the logarithm of x to base b is written as logb (x), logb x, or simply log x without the explicit base.

Step-by-step explanation:

Given :

$log \sqrt{2}$ 32

To Find:

The value of $log \sqrt{2}$ 32

Solution :

$log \sqrt{2}$ 32

=  $\frac{log 32}{log \sqrt{2}}$  = $\frac{log 2^{5} }{log 2^\frac{1}{2}{} }$

= $\frac{5 log 2}{\frac{1}{2} log 2}$

∴ log $x^{n}$ = n log $x$

= 5 × 2

= 10

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